solve the system of equations: x=6y-3 , 2x+7y=13

Answer 1

To solve this system of equations, we will first substitute the value of x from the first equation into the second equation.

Given that x=6y-3, we substitute this into the second equation 2x + 7y = 13:

2(6y-3) + 7y = 13
12y - 6 + 7y = 13
19y - 6 = 13
19y = 19
y = 1

Now that we have found the value of y, we can substitute it back into the first equation to find the value of x:

x = 6(1) - 3
x = 6 - 3
x = 3

Therefore, the solution to the system of equations is x = 3 and y = 1.