Question
How many Liters would 60.0 g of CO₂ occupy?
Answers
GPT 3.5
To calculate the volume of 60.0 g of CO₂, we first need to convert the mass to moles using the molar mass of CO₂.
Molar mass of CO₂ = 44.01 g/mol
Number of moles = Mass / Molar mass
Number of moles = 60.0 g / 44.01 g/mol ≈ 1.36 mol
Now, we can use the ideal gas law to calculate the volume:
PV = nRT
Where:
P = pressure (assume standard pressure of 1 atm)
V = volume
n = number of moles
R = ideal gas constant (0.0821 L.atm/mol.K)
T = temperature (assume room temperature of 298 K)
Rearranging the equation to solve for V:
V = (nRT) / P
V = (1.36 mol * 0.0821 L.atm/mol.K * 298 K) / 1 atm
V ≈ 35.0 L
Therefore, 60.0 g of CO₂ would occupy approximately 35.0 liters.
Molar mass of CO₂ = 44.01 g/mol
Number of moles = Mass / Molar mass
Number of moles = 60.0 g / 44.01 g/mol ≈ 1.36 mol
Now, we can use the ideal gas law to calculate the volume:
PV = nRT
Where:
P = pressure (assume standard pressure of 1 atm)
V = volume
n = number of moles
R = ideal gas constant (0.0821 L.atm/mol.K)
T = temperature (assume room temperature of 298 K)
Rearranging the equation to solve for V:
V = (nRT) / P
V = (1.36 mol * 0.0821 L.atm/mol.K * 298 K) / 1 atm
V ≈ 35.0 L
Therefore, 60.0 g of CO₂ would occupy approximately 35.0 liters.