Question
calculate the time taken for the diver to hit the water from a height of 18.0m
Answers
GPT 3.5
To calculate the time taken for the diver to hit the water from a height of 18.0m, we can use the equation:
s = ut + (1/2)at^2
Where:
s = distance (18.0m)
u = initial velocity (0 m/s as the diver starts from rest)
a = acceleration due to gravity (-9.8 m/s^2, downward direction)
t = time
Plugging in the values:
18.0 = 0 + (1/2)(-9.8)t^2
18.0 = -4.9t^2
t^2 = 18.0 / -4.9
t^2 = 3.6734
t = sqrt(3.6734)
t ≈ 1.92 seconds
Therefore, the time taken for the diver to hit the water from a height of 18.0m is approximately 1.92 seconds.
s = ut + (1/2)at^2
Where:
s = distance (18.0m)
u = initial velocity (0 m/s as the diver starts from rest)
a = acceleration due to gravity (-9.8 m/s^2, downward direction)
t = time
Plugging in the values:
18.0 = 0 + (1/2)(-9.8)t^2
18.0 = -4.9t^2
t^2 = 18.0 / -4.9
t^2 = 3.6734
t = sqrt(3.6734)
t ≈ 1.92 seconds
Therefore, the time taken for the diver to hit the water from a height of 18.0m is approximately 1.92 seconds.