Asked by Unknown

A 2.2 m-long string is fixed at both ends and tightened until the wave speed is 50 m/s.What is the frequency of the standing wave shown in the figure?
picture has 6 waves
Answered by bobpursley
If it is truly six waves, then the 2.2m is six wavelengths long.

f*Lambda=50
Answered by Unknown
how did you arrive at 50 because picture might have 7 nodes
Answered by bobpursley
50 was given as wavespeed.
I cant determine how many wavelengths the string is, you will have to do that.
Answered by Unknown
but how do i do it
Answered by H-Bomb
Count the cycles. From equilibrium up to the crest, down the trough, and back to equilibrium (like a complete sinusoidal wave)--that is one cycle.

Find the time: the distance of the string, divide it by the speed. This is the basic concept of velocity=displacement/time. You just solve for time.

You have seconds and you have cycles. What is frequency? Cycles per second. There.
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