Question

which of the following systems have a solution of (-2, 1)

2x−y=−5
and x+2y=10
2 x minus y is equal to negative 5 and x plus 2 y is equal to 10

x−4y=8
and 3x+10=−2y
x minus 4 y is equal to 8 and 3 x plus 10 is equal to negative 2 y

y=−32x−2
and 2x−y=−5
y is equal to negative 3 over 2 x minus 2 and 2 x minus y is equal to negative 5

y=−2x−2
and 2x−2y=5

Answer 1

show how you got that

Answer 2

The first system, 2x−y=−5 and x+2y=10, has a solution of (-2, 1).

Answer 3

To find the solution to a system of equations, you need to solve it simultaneously.

Given system:
2x − y = −5
x + 2y = 10

Let's solve this system of equations by the method of substitution:

From the first equation:
y = 2x + 5

Now substitute this value of y in the second equation:
x + 2(2x + 5) = 10
x + 4x + 10 = 10
5x + 10 = 10
5x = 0
x = 0

Substitute x = 0 back into y = 2x + 5:
y = 2(0) + 5
y = 5

So, the solution to the first system of equations is x = 0 and y = 5, not (-2, 1). I made a mistake in the initial assessment. Thank you for pointing it out.