To multiply the second equation to eliminate y, you would multiply the entire equation by 3.
1. 6x + 3y = 14
2. 9x + 6y = 30
Now you can subtract the first equation from the second equation to eliminate y:
(9x + 6y) - (6x + 3y) = 30 - 14
3x = 16
x = 16/3
Now substitute x back into the first equation to solve for y:
6(16/3) + 3y = 14
32 + 3y = 14
3y = -18
y = -6
Therefore, the solution to the system of equations using the elimination method is x = 16/3 and y = -6.