Asked by Reen
f'(x) = (x^2-1)/x
Answers
Answered by
Reen
sorry, i meant what is the antiderivative of
f'(x) = (x^2-1)/x
f'(x) = (x^2-1)/x
Answered by
drwls
Write f(x) as
f(x) = x - 1/x, and integrate it one term at a time.
The integral (or "antiderivative", if you insist on using that term) of x is (x^2)/2. The integral of -1/x is -ln x. An arbitrary constant term can be added to the integral.
f(x) = x - 1/x, and integrate it one term at a time.
The integral (or "antiderivative", if you insist on using that term) of x is (x^2)/2. The integral of -1/x is -ln x. An arbitrary constant term can be added to the integral.
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