Asked by Reen
find f(x)
f'(x) = (x^2-1)/x^(-1)
f'(x) = (x^2-1)/x^(-1)
Answers
Answered by
bobpursley
What exactly was wrong with my last response?
Answered by
Reen
i just didn't understand how you got to that point. And i havn't learned integrals yet. I was hoping someone else could give me a different perspective as to how to answer it.
Answered by
Reen
im sorry. i think it was because i wrote it wrong.
i meant
f'(x) = (x^2-1)/x
i meant
f'(x) = (x^2-1)/x
Answered by
Collin
Note that f'(x) can be rewritten algebraically a f'(x)= x -(1/x).
Now, take the integral (anti-drivitive)
of f'(x) with respect to 'x' to obtain
f(x).
So,
Int(x-(1/x),x)=((x^(2))/2)-ln(abs(x))+C
To understand this you must first look at the rules of integrals.
By the way in some computer programs if you enter this, for some reason they don't like the ln(abs(x)) even though this is correct so just make it ln(x).
Now, take the integral (anti-drivitive)
of f'(x) with respect to 'x' to obtain
f(x).
So,
Int(x-(1/x),x)=((x^(2))/2)-ln(abs(x))+C
To understand this you must first look at the rules of integrals.
By the way in some computer programs if you enter this, for some reason they don't like the ln(abs(x)) even though this is correct so just make it ln(x).
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