Solve the system of equations by substitution.%0D%0A%0D%0A−4x+4y=−40%0D%0A−%0D%0A4%0D%0A%0D%0A+%0D%0A4%0D%0A%0D%0A=%0D%0A−%0D%0A40%0D%0A%0D%0Ay=3x−4

Answer 1

To solve this system of equations by substitution, we need to first solve for y in terms of x in the second equation, and then substitute that expression into the first equation.

Given:

y = 3x - 4

We will substitute y in the first equation:

-4x + 4(3x - 4) = -40
-4x + 12x - 16 = -40
8x - 16 = -40
8x = -24
x = -3

Now, we will substitute x back into the equation y = 3x - 4 to solve for y:

y = 3(-3) - 4
y = -9 - 4
y = -13

Therefore, the solution to the system of equations is x = -3 and y = -13.