To find the slope of the line tangent to the polar curve at θ = π, we first need to find the slope of the tangent line in terms of the polar coordinates. The slope of the tangent line to a polar curve at a point (r, θ) is given by dy/dx = (dy/dθ)/(dx/dθ).
Since r = f(θ), we have r' = f'(θ). So the slope of the tangent line to the polar curve r = f(θ) at θ = π is f'(π).
Given that f'(π) = -3, the slope of the line tangent to the polar curve r = f(θ) at θ = π is -3.
let f be a differentiable function such that f(pi)=2 and f'(pi)=-3. what is the slope of the line tangent to the polar curve r=f(theta) at theta=pi
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