what is the missing exponent in the following equation?
e^/e^65=e^38
3 answers
27
thats not the correct answer
Apologies for the error. Let's try solving it again.
e^x / e^65 = e^38
Using the rule of exponents which states that when dividing two numbers with the same base, we subtract the exponents, we can use this information to find the missing exponent.
e^(x-65) = e^38
Now, we can set the exponents equal to each other:
x - 65 = 38
Adding 65 to both sides:
x = 103
Therefore, the missing exponent in the equation is 103.
e^x / e^65 = e^38
Using the rule of exponents which states that when dividing two numbers with the same base, we subtract the exponents, we can use this information to find the missing exponent.
e^(x-65) = e^38
Now, we can set the exponents equal to each other:
x - 65 = 38
Adding 65 to both sides:
x = 103
Therefore, the missing exponent in the equation is 103.