Asked by Alice
At room temperature (25 degrees C) butane is a mixture of 72% anti and 28% gauche conformations. Calculate the difference in energy between the gauche and anti confromations.
This is how I calculated it but I am not sure I am right:
Boltzmann equation: N2/N1 = exp(-(E2-E1)/RT)
By rearranging: E2-E1 = -RTln(N2/N1)
E2-E1 = -8.314JK^-1mol^-1 x 298K x ln(28/72)
= 2340Jmol^-1
=0.56kcalmol-1
I looked up the correct value on the internet and found it to be around 0.9kcalmol^-1. Have I gone wrong somewhere?
This is how I calculated it but I am not sure I am right:
Boltzmann equation: N2/N1 = exp(-(E2-E1)/RT)
By rearranging: E2-E1 = -RTln(N2/N1)
E2-E1 = -8.314JK^-1mol^-1 x 298K x ln(28/72)
= 2340Jmol^-1
=0.56kcalmol-1
I looked up the correct value on the internet and found it to be around 0.9kcalmol^-1. Have I gone wrong somewhere?
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