The circumference of a sphere was measured to be 74.000 cm with a possible error of 0.50000 cm. Use linear approximation to estimate the maximum error in the calculated surface area?
Also Estimate the relative error in the calculated surface area.
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This question was asked and answered yesterday. The circumference relative error is 0.5/74 = 0.675%. The area relative error is twice that, or 1.35%. Calculate the surface area. 1.35% of that is the maximum error.
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