Asked by Joe
A wholesaler mixed coffee beans worth $6/kg with another kind worth $8.80/kg. The 16kg mixture was worth $6.70/kg. How many kilograms of each type was used?
Answers
Answered by
Reiny
Let the amount of the $6 mixture used be x kg
let the amount of the $8.80 mixture be 16-x kg
then
6x + 8.8(16-x) = 6.7(16)
solve for x
let the amount of the $8.80 mixture be 16-x kg
then
6x + 8.8(16-x) = 6.7(16)
solve for x
Answered by
mo
thnx SO MUCH
Answered by
Robby
6x+1408-88x=1072
you may move the decimal 1 place if you want
1408-82x=1072
1408-1072=82x
336=88x
x=336/88
you may move the decimal 1 place if you want
1408-82x=1072
1408-1072=82x
336=88x
x=336/88
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.