Question
A wholesaler mixed coffee beans worth $6/kg with another kind worth $8.80/kg. The 16kg mixture was worth $6.70/kg. How many kilograms of each type was used?
Answers
Reiny
Let the amount of the $6 mixture used be x kg
let the amount of the $8.80 mixture be 16-x kg
then
6x + 8.8(16-x) = 6.7(16)
solve for x
let the amount of the $8.80 mixture be 16-x kg
then
6x + 8.8(16-x) = 6.7(16)
solve for x
mo
thnx SO MUCH
Robby
6x+1408-88x=1072
you may move the decimal 1 place if you want
1408-82x=1072
1408-1072=82x
336=88x
x=336/88
you may move the decimal 1 place if you want
1408-82x=1072
1408-1072=82x
336=88x
x=336/88