Asked by Joe

A wholesaler mixed coffee beans worth $6/kg with another kind worth $8.80/kg. The 16kg mixture was worth $6.70/kg. How many kilograms of each type was used?
Answered by Reiny
Let the amount of the $6 mixture used be x kg
let the amount of the $8.80 mixture be 16-x kg

then
6x + 8.8(16-x) = 6.7(16)

solve for x
Answered by mo
thnx SO MUCH
Answered by Robby
6x+1408-88x=1072
you may move the decimal 1 place if you want
1408-82x=1072
1408-1072=82x
336=88x
x=336/88
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