Weight of ethanol = 12.4 g
Volume of mouthwash = 65 mL
% weight = (weight of component/total weight of solution) x 100
% weight of ethanol = (12.4 g/65 mL) x 100 = 19.08%
% volume = (volume of component/total volume of solution) x 100
% volume of ethanol = (12.4 g/65 mL) x 100 = 19.08%
A commercial mouthwash contains 12.4 g of ethanol and 0.049 g of antiseptic in each 65. -mL portion. Calculate the
component. Be sure each of your answer entries has the correct number of significant figures.
Part 1 of 2
weight
volume
percent concentration for each
%
weight
volume
ethanol
1 answer
1 answer