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To use linear approximation (the tangent line) to approximate 1.6^3, we need to substitute the value x = 1.6 into the equation of the tangent line.
The equation of the tangent line to f(x) = x^3 at x = 2 is given as y = 12x - 16.
So, let's substitute x = 1.6 into the equation:
y = 12(1.6) - 16
y = 19.2 - 16
y = 3.2
Therefore, using linear approximation, 1.6^3 is approximated to be 3.2.