If R = 3 in and H = 6 in, what is the approximate surface area of the cylinder? (Use 3.14 for pi.)

Answer 1

To find the surface area of a cylinder, you need to find the area of the two circular bases and the lateral surface area.

First, let's find the area of the two circular bases:
Area of a circle = πr^2
Area of the top base = π(3 in)^2 = 9π sq in
Area of the bottom base = π(3 in)^2 = 9π sq in

Now, let's find the lateral surface area:
Lateral surface area = 2πrh
Lateral surface area = 2π(3 in)(6 in) = 36π sq in

Now, calculate the total surface area by adding the areas of the two bases and the lateral surface area:
Total surface area = 9π + 9π + 36π = 54π sq in

Now, substitute 3.14 for π:
Total surface area ≈ 54 * 3.14 ≈ 169.56 sq in

Therefore, the approximate surface area of the cylinder is approximately 169.56 square inches.