Asked by Anonymous
When a pilot banks an aircraft moving at a speed, v, in metres per second, at an angle a, the radius of the turn that results is given by the formula:
r = v^2/g * tan(pi/2 - a)
where g is the accelatation due to gravity, or 9.8 m/s^2.
Use an appropriate equivalent trigonometric expression to show that this formula can be simplified to:
r= v^2 / (g*tana)
r = v^2/g * tan(pi/2 - a)
where g is the accelatation due to gravity, or 9.8 m/s^2.
Use an appropriate equivalent trigonometric expression to show that this formula can be simplified to:
r= v^2 / (g*tana)
Answers
Answered by
Reiny
pi/2-a and a are complementary angles.
the trig ratio of any angle is the co-ratio of the complement of that angle.
e.g. sin 70 = cos 20
sec 25 = csc 65
and tan (pi/2 - a) = cot a
so
r = v^2/g * tan(pi/2 - a)
= v^2/g * cot a
= v^2/g * 1/tan a
= v^2/(g*tan a)
the trig ratio of any angle is the co-ratio of the complement of that angle.
e.g. sin 70 = cos 20
sec 25 = csc 65
and tan (pi/2 - a) = cot a
so
r = v^2/g * tan(pi/2 - a)
= v^2/g * cot a
= v^2/g * 1/tan a
= v^2/(g*tan a)
Answered by
susana
explain why tan 60degree=root3.
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