Question

Given: y varies directly as x.

If y = 5 when x = 4, what is the value of y when x = 12?

A 9.69.6
B 1010
C 1212
D 15

Answer 1

Since y varies directly as x, the equation can be written as y = kx, where k is the constant of variation.

To find the value of k, we can use the given values y = 5 when x = 4:

5 = k(4)
k = 5/4
k = 1.25

Now we can substitute k back into the equation to find the value of y when x = 12:

y = 1.25(12)
y = 15

Therefore, the value of y when x = 12 is 15.

The correct answer is:

D) 15