Question
A 500.0-mL sodium iodide (NaI) solution was prepared by dissolving 37.7g of solid NaI in water. Chlorine gas was bubbled through a 100.0-mL sample of this solution until the reaction was complete. How many grams of molecular iodine were produced?
Answers
bobpursley
How many grams of I is in 37.7g NaI ?
I can figure out that 37.7g NaI = .252 mol NaI. I have no clue how to solve this one.. I don't want the answer I just need the steps to get to it
Related Questions
What is the molarity of a solution prepared by dissolving 2.41 g of potassium iodide, KI in 100 mL o...
Iodine can be prepared by bubbling chlorine gas through an aqueous solution of sodium iodide:
2Na...
solution of 0.148 M sodium iodide for an experiment in lab, using a 500 mL volumetric flask. How muc...
A buffer was prepared by dissolving 0.40 mol of benzoic acid (Ka=6.3*10^-5) and 0.50 mol of sodium b...