10+8x>2 on a number line

Answer 1

To graph the inequality 10 + 8x > 2 on a number line, we first need to isolate the variable x.

Subtract 10 from both sides:
8x > -8

Divide by 8:
x > -1

Now we can graph this inequality on the number line.

-1 is an open circle because x is not equal to -1. Since x is greater than -1, we shade the number line to the right of -1.

The graph will look like this:

----o---->

Where o represents the open circle at -1 and the arrow points to the right to show that x is greater than -1.