Can you explain

Question

What is the sum of x - 4x^2 + 6 and - (2x^2 + 8 - 3x)

Answer 1

To find the sum of x - 4x^2 + 6 and - (2x^2 + 8 - 3x), you first need to distribute the negative sign outside the parentheses:

-1 * (2x^2 + 8 - 3x) = -2x^2 - 8 + 3x

Now, you can add the two expressions together:

x - 4x^2 + 6 + (-2x^2 - 8 + 3x)

Rearranging the terms:

x - 4x^2 - 2x^2 + 3x + 6 - 8

Combining like terms:

-x^2 + 4x - 2

So, the sum of x - 4x^2 + 6 and - (2x^2 + 8 - 3x) is -x^2 + 4x - 2.