a) To calculate the output power of the train, we first need to determine the total resistance the train is facing at 20m/s. This can be done using the formula:
Total resistance = Frictional resistance + Air resistance
Given that the frictional resistance is 1500N and the air resistance is not provided, we will assume the air resistance to be negligible for the calculation.
Total resistance = 1500N
Next, we can calculate the output power of the train using the formula:
Output power = Force x Velocity
Output power = Total resistance x Velocity
Output power = 1500N x 20m/s
Output power = 30000 watts
Convert watts to kilowatts:
Output power = 30000 watts = 30 kW
Therefore, the output power of the train is 30 kW.
b) The efficiency of the train can be calculated using the formula:
Efficiency = (Output power / Input power) x 100%
Given that the input power is 200 kW, we can substitute the values into the formula:
Efficiency = (30 kW / 200 kW) x 100%
Efficiency = 0.15 x 100%
Efficiency = 15%
Therefore, the efficiency of the train is 15%.
A locomotive train is experiencing a frictional resistance when traveling at 20m/s and the resistance is 1500N. The power development by its engine is 200kW
Calculate
a) The output power of the train
b) the efficiency of the train
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