The surface area of the rain barrel can be calculated by finding the lateral surface area of the cylinder and the surface area of the top and bottom circles.
1. Lateral surface area of cylinder:
Lateral surface area = 2πrh
r = radius = diameter / 2 = 24 / 2 = 12 inches
h = height = 48 inches
Lateral surface area = 2 * 3.14 * 12 * 48 = 3619.52 in²
2. Surface area of top and bottom circles:
Surface area = 2πr²
r = radius = diameter / 2 = 12 inches
Surface area = 2 * 3.14 * 12² = 904.32 in²
3. Total surface area:
Total surface area = Lateral surface area + 2 * Surface area
Total surface area = 3619.52 + 2 * 904.32
Total surface area = 5428.16 in²
Therefore, the surface area of the rain barrel is 5428.2 in² (rounded to the nearest tenth).
Joseph has a rain barrel in the shape of a cylinder with a height of 48 inches and a diameter of 24 inches. What is the surface area of the rain barrel? Use 3.14 for π and round to the nearest tenth.(1 point)
in.2
1 answer