Question
                What is the value that satisfies the equation? 27^2x = 9^x+4
            
            
        Answers
                    Answered by
            oobleck
            
    do you ever check your answers?
27^(2(-2)) = 27 ^-4 = 1/531441
9^(-2+4) = 9^2 = 81
so, what is x?
27^2x = (3^3)^(2x) = 3^(6x)
9^x+4 = (3^2)^(x+4) = 3^(2x+8)
so, now we have
6x = 2x+8
4x = 8
x = 2
    
27^(2(-2)) = 27 ^-4 = 1/531441
9^(-2+4) = 9^2 = 81
so, what is x?
27^2x = (3^3)^(2x) = 3^(6x)
9^x+4 = (3^2)^(x+4) = 3^(2x+8)
so, now we have
6x = 2x+8
4x = 8
x = 2
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