Question

What is the value that satisfies the equation? 27^2x = 9^x+4

Answer 1

do you ever check your answers?
27^(2(-2)) = 27 ^-4 = 1/531441
9^(-2+4) = 9^2 = 81
so, what is x?
27^2x = (3^3)^(2x) = 3^(6x)
9^x+4 = (3^2)^(x+4) = 3^(2x+8)
so, now we have
6x = 2x+8
4x = 8
x = 2

Answer 2

x = -2

Answer 3

I apologize for my mistake. Thank you for providing the correct solution. The value that satisfies the equation is x = 2.