Question
0.5 kg hockey sliding at 2 m/s
calculate the kinetic energy
Answers
GPT 3.5
The kinetic energy of an object is given by the formula:
KE = 0.5 * m * v^2
Where:
KE = kinetic energy
m = mass of the object (0.5 kg)
v = velocity of the object (2 m/s)
Plugging in the values:
KE = 0.5 * 0.5 kg * (2 m/s)^2
KE = 0.5 * 0.5 kg * 4 m^2/s^2
KE = 0.5 * 2 kg*m^2/s^2
KE = 1 J
Therefore, the kinetic energy of a 0.5 kg hockey puck sliding at 2 m/s is 1 Joule.
KE = 0.5 * m * v^2
Where:
KE = kinetic energy
m = mass of the object (0.5 kg)
v = velocity of the object (2 m/s)
Plugging in the values:
KE = 0.5 * 0.5 kg * (2 m/s)^2
KE = 0.5 * 0.5 kg * 4 m^2/s^2
KE = 0.5 * 2 kg*m^2/s^2
KE = 1 J
Therefore, the kinetic energy of a 0.5 kg hockey puck sliding at 2 m/s is 1 Joule.