39 in.2
Each face of the pyramid would be a triangle, and the total area of the faces would be the sum of the four triangular faces. Each triangular face has an area of (1/2)bh, where b is the base length (3 inches) and h is the height (5 inches).
(1/2) * 3 * 5 = 7.5 square inches
Multiply that by 4 since there are four triangular faces:
7.5 * 4 = 30 in.2
Therefore, 30 square inches of icing are needed for the faces of the dessert.
Use the image to answer the question.
An illustration shows a net diagram. The center of the diagram is a square with dashed lines marking its sides. Each side forms the base of one of four triangles extending outward from the square. The sides of the square measure 3 inches, and the perpendicular height of the triangular faces measures 5 inches.
A chocolate dessert is in the shape of a square pyramid. The pyramid is represented with a net. How many square inches of icing are needed for the faces of the dessert?
(1 point)
Responses
60 in.2
60 in. squared
39 in.2
39 in. squared
30 in.2
30 in. squared
69 in.2
1 answer
1 answer