Question
A helium balloon is at a height of 1,200 after two minutes in flightThe balloon finally pops after seven minutes in flight, at a height of 10,500 ftWhat is the average rate of change in height for the balloon over this period of time? (1 point) 9, 300fL / m * in; 1,033.33 ft./min.; 1, 860fL / m * in; 2.34fL / m * in
Answers
GPT 3.5
The average rate of change in height for the balloon can be calculated by dividing the total change in height by the total time.
Total change in height = 10,500 ft - 1,200 ft = 9,300 ft
Total time = 7 minutes - 2 minutes = 5 minutes
Average rate of change in height = 9,300 ft / 5 min = 1,860 ft/min
Therefore, the average rate of change in height for the balloon over this period of time is 1,860 ft/min.
Total change in height = 10,500 ft - 1,200 ft = 9,300 ft
Total time = 7 minutes - 2 minutes = 5 minutes
Average rate of change in height = 9,300 ft / 5 min = 1,860 ft/min
Therefore, the average rate of change in height for the balloon over this period of time is 1,860 ft/min.