Asked by Shane
Calculate the velocity of a satellite moving in a stable circular orbit about the Earth at a height of 2600 km.
Answers
Answered by
bobpursley
Fgravity=Fcentripetal
GMearth/(radEarth+ 2600km)^2= mv^2/(radearth+2600)
solve for v.
change all distances to meters..
GMearth/(radEarth+ 2600km)^2= mv^2/(radearth+2600)
solve for v.
change all distances to meters..
Answered by
Shane
would m be the mass of the earth?
Answered by
bobpursley
m is mass satellite.
And I forgot one on the left of that line.
Here is is corrected:
GMearth*m/(radEarth+ 2600km)^2= mv^2/(radearth+2600)
And I forgot one on the left of that line.
Here is is corrected:
GMearth*m/(radEarth+ 2600km)^2= mv^2/(radearth+2600)
Answered by
Anonymous
does that mean the mass of the statellite cancels? because the mass of the statellite isnt given
Answered by
bobpursley
yes, the mass of the satellite divides out.
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