Asked by Anonymous
Four 7.5 kg spheres are located at the corners of a square of side 0.74 m. Calculate the magnitude and direction of the gravitational force on one sphere due to the other three.
Answers
Answered by
bobpursley
Use symettry. YOu know the force will be diagonal.
the side components will be
2G*m^2/.74^2 Cos45
and the diagonal will be
G*m^2/(.74*1.414)^2
add
the side components will be
2G*m^2/.74^2 Cos45
and the diagonal will be
G*m^2/(.74*1.414)^2
add
Answered by
Anonymous
i got 1.71E-8 and that was wrong and then i got 1.03E-8 and it was still wrong
Answered by
susan
with sig figs the answer should be
2.0*10^-8 N towards the center of the circle
2.0*10^-8 N towards the center of the circle
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