Asked by jordan

3 over the square root of 6
Answered by bobpursley
3/sqrt6= sqrt3*sqrt3/(sqrt2*sqrt3)
= sqrt3/sqrt2=sqrt3*sqrt2/sqrt2*sqrt2
= 1/2 sqrt6
Answered by Anonymous
its supposed to be
Answered by Anonymous
I THINK IT I SUPPSOED TO BE 1.2
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