Question
4.0g of sodium hydroxide in 250cm3 of solution contains?
Answers
GPT 3.5
To determine the concentration of sodium hydroxide in the solution, we need to calculate the molarity using the formula:
Molarity (M) = (moles of solute) / (volume of solution in liters)
First, calculate the moles of sodium hydroxide using its molar mass:
Molar mass of NaOH = 23g/mol (for Na) + 16g/mol (for O) + 1g/mol (for H) = 40g/mol
moles of NaOH = 4g / 40g/mol = 0.1 moles
Convert the volume of the solution from cm3 to liters:
250 cm3 = 0.25 liters
Now, plug the values into the formula to calculate the molarity:
Molarity (M) = 0.1 moles / 0.25 liters = 0.4 M
Therefore, the solution contains 0.4 moles of sodium hydroxide per liter.
Molarity (M) = (moles of solute) / (volume of solution in liters)
First, calculate the moles of sodium hydroxide using its molar mass:
Molar mass of NaOH = 23g/mol (for Na) + 16g/mol (for O) + 1g/mol (for H) = 40g/mol
moles of NaOH = 4g / 40g/mol = 0.1 moles
Convert the volume of the solution from cm3 to liters:
250 cm3 = 0.25 liters
Now, plug the values into the formula to calculate the molarity:
Molarity (M) = 0.1 moles / 0.25 liters = 0.4 M
Therefore, the solution contains 0.4 moles of sodium hydroxide per liter.