Question

I am trying to figure out the zeroes of 2x^2-7x-30. I did this graphically in a way that matched up with the answers in my book, however, I couldn't get it by distributing. I tried (2x+-10)(x+3) but that didn't get -7x in the middle as logic told me it should. How would you then do this?

Answer 1

2x^2-7x-30 = (2x +5)(x - 6)

Answer 2

ask for help