Solving Systems by Substitution

-x - 6y=15
y = 6x +16

11 answers

We can solve this system of equations by substituting the second equation into the first equation.

First, plug in the value of y from the second equation into the first equation:

-x - 6(6x +16) = 15

Simplify the equation by distributing the -6:

-x - 36x - 96 = 15

Combine like terms:

-37x - 96 = 15

Add 96 to both sides:

-37x = 111

Divide by -37 on both sides to solve for x:

x = -3

Now that we have found the value of x, we can substitute it back into the second equation to find the value of y:

y = 6(-3) + 16
y = -18 + 16
y = -2

Therefore, the solution to the system of equations is x = -3 and y = -2.
-6 .*23
The product of -6 and 23 is:

-6 * 23 = -138
16 +138
The sum of 16 and 138 is:

16 + 138 = 154
-21 + 23
The sum of -21 and 23 is:

-21 + 23 = 2
-21 - 22
The difference between -21 and 22 is:

-21 - 22 = -43
-15 +2
The sum of -15 and 2 is:

-15 + 2 = -13