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When a falling meteor is at a distance above the Earth's surface of 2.78 times the Earth's radius, what is its free-fall acceleration caused by the gravitational force exerted on it?
15 years ago

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drwls
The gravitational acceleration varies inversely with the square of the distance from the center of the Earth. If the value at the earth's surface is g, at the higher altitude it is
g/(2.78)^2
15 years ago

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