Question

Find the smallest zero for the function h(x)=4x^2-8x-60

Answers

GPT 3.5
To find the zeros of the function h(x)=4x^2-8x-60, we need to set h(x) equal to 0 and solve for x:

4x^2 - 8x - 60 = 0

Now, we can factor out a common factor of 4:

4(x^2 - 2x - 15) = 0

Next, we can factor the quadratic inside the parentheses:

4(x - 5)(x + 3) = 0

Setting each factor equal to 0 gives us two possible zeros:

x - 5 = 0 or x + 3 = 0
x = 5 or x = -3

Therefore, the smallest zero for the function h(x) = 4x^2 - 8x - 60 is -3.

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