Question
The LRT train in Edmonton starts from rest at the Clareview station and accelerates at a rate of 4.0 m/s^2 for the first 6.0s. The train then maintains a constant speed for the next 45.0s.
Calculate the trains velocity after 6.0s have elapsed.
Calculate the trains velocity after 6.0s have elapsed.
Answers
GPT 3.5
To calculate the train's velocity after 6.0s have elapsed, we can use the equation:
v = u + at
where:
v = final velocity
u = initial velocity (which is 0 m/s since the train starts from rest)
a = acceleration (4.0 m/s^2)
t = time (6.0s)
Plugging in the values:
v = 0 + (4.0 m/s^2)(6.0s)
v = 0 + 24.0
v = 24.0 m/s
Therefore, the train's velocity after 6.0s have elapsed is 24.0 m/s.
v = u + at
where:
v = final velocity
u = initial velocity (which is 0 m/s since the train starts from rest)
a = acceleration (4.0 m/s^2)
t = time (6.0s)
Plugging in the values:
v = 0 + (4.0 m/s^2)(6.0s)
v = 0 + 24.0
v = 24.0 m/s
Therefore, the train's velocity after 6.0s have elapsed is 24.0 m/s.