To calculate the train's velocity after 6.0s have elapsed, we can use the equation:
v = u + at
where:
v = final velocity
u = initial velocity (which is 0 m/s since the train starts from rest)
a = acceleration (4.0 m/s^2)
t = time (6.0s)
Plugging in the values:
v = 0 + (4.0 m/s^2)(6.0s)
v = 0 + 24.0
v = 24.0 m/s
Therefore, the train's velocity after 6.0s have elapsed is 24.0 m/s.
The LRT train in Edmonton starts from rest at the Clareview station and accelerates at a rate of 4.0 m/s^2 for the first 6.0s. The train then maintains a constant speed for the next 45.0s.
Calculate the trains velocity after 6.0s have elapsed.
1 answer
1 answer