what is an objects acceleration if it tavels at a speed of 1200 m/s and stops within a distance of 1.5 cm

Answer 1

To calculate the acceleration of the object, we can use the equation of motion:

v^2 = u^2 + 2as

where:
v = final velocity = 0 m/s (since the object stops)
u = initial velocity = 1200 m/s
a = acceleration
s = distance = 0.015 m

Rearranging the equation to solve for acceleration (a), we get:

a = (v^2 - u^2) / 2s
a = (0^2 - 1200^2) / (2 * 0.015)
a = (-1440000) / 0.03
a = -48000000 m/s^2

So, the acceleration of the object when it stops within a distance of 1.5 cm is -48000000 m/s^2. The negative sign indicates that the acceleration is in the opposite direction to the initial velocity.