an object moves forward from rest with a constant acceleration if the object moves 90.0 m in 7.00sfind its velocity after 7.00

Answer 1

To find the velocity after 7.00 seconds, we can use the following kinematic equation:

v = u + at

Where:
v = final velocity
u = initial velocity (in this case, since the object starts from rest, u = 0 m/s)
a = acceleration
t = time

Given that the object moves with a constant acceleration, we can find the acceleration using the following equation which relates distance, initial velocity, time, and acceleration:

s = ut + (1/2)at^2

Rearranging for acceleration (a), we have:

a = 2(s - ut)/t^2

Given:
s = 90 m
u = 0 m/s
t = 7.00 s

a = 2(90 - 0*7)/(7^2) = 180/49 m/s^2

Now, subtitute the known values into the first kinematic equation:

v = 0 + (180/49)*7
v = 1260/49
v = 25.714 m/s

Therefore, the velocity of the object after 7.00 seconds is 25.714 m/s.