what is the acceleration of an object starting from rest and than 2.75 * 10^-3s later moving with a velocity of 560m/s [forward]

Answer 1

To find the acceleration of the object, we will use the formula:

Acceleration = (Final Velocity - Initial Velocity) / Time

Given:
Initial Velocity (u) = 0 m/s
Final Velocity (v) = 560 m/s
Time (t) = 2.75 * 10^-3 s

Acceleration = (560 m/s - 0 m/s) / 2.75 * 10^-3 s
Acceleration = 560 m/s / 2.75 * 10^-3 s
Acceleration = 203636.36 m/s^2

Therefore, the acceleration of the object is 203636.36 m/s^2.