Asked by arriell
How long will it take a 2.30 x 10^3 kg truck to go from 22.2 m/s to a complete stop if acted on by a force of -1.26 x 10^4 N? what would be its stopping distance?
Answers
Answered by
bobpursley
F*time=mass*changeinvelocity
solve for time.
for distance...
1/2 m vi^2= force*distance solve for distance.
solve for time.
for distance...
1/2 m vi^2= force*distance solve for distance.
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