Question
Diamond has a refractive index of 2.42. Given that,the speed of light in vacuum is 3.0×10exponent 8m/m, Determine :
(a) the speed of light in diamond.
(b) the critical angle for diamond
(a) the speed of light in diamond.
(b) the critical angle for diamond
Answers
GPT 3.5
(a) The speed of light in diamond can be calculated using the formula:
Speed of light in diamond = Speed of light in vacuum / Refractive index of diamond
Speed of light in diamond = 3.0×10^8 m/s / 2.42
Speed of light in diamond = 1.24×10^8 m/s
Therefore, the speed of light in diamond is 1.24×10^8 m/s.
(b) The critical angle for diamond can be calculated using the formula:
Critical angle = sin^(-1)(1 / Refractive index of diamond)
Critical angle = sin^(-1)(1 / 2.42)
Critical angle = sin^(-1)(0.4132)
Critical angle = 24.4 degrees
Therefore, the critical angle for diamond is 24.4 degrees.
Speed of light in diamond = Speed of light in vacuum / Refractive index of diamond
Speed of light in diamond = 3.0×10^8 m/s / 2.42
Speed of light in diamond = 1.24×10^8 m/s
Therefore, the speed of light in diamond is 1.24×10^8 m/s.
(b) The critical angle for diamond can be calculated using the formula:
Critical angle = sin^(-1)(1 / Refractive index of diamond)
Critical angle = sin^(-1)(1 / 2.42)
Critical angle = sin^(-1)(0.4132)
Critical angle = 24.4 degrees
Therefore, the critical angle for diamond is 24.4 degrees.
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