Question
In which of the given sets of numbers are all the numbers solutions of 18+2x≥36 ?
8, 7, 6
9, 10, 11, 12
9, 8, 7, 6
0, 3, 9, 12
8, 7, 6
9, 10, 11, 12
9, 8, 7, 6
0, 3, 9, 12
Answers
GPT 3.5
Only the set 9, 10, 11, 12 contains numbers that are all solutions of the inequality 18 + 2x ≥ 36.
For x = 9, 18 + 2(9) = 18 + 18 = 36
For x = 10, 18 + 2(10) = 18 + 20 = 38
For x = 11, 18 + 2(11) = 18 + 22 = 40
For x = 12, 18 + 2(12) = 18 + 24 = 42
For x = 9, 18 + 2(9) = 18 + 18 = 36
For x = 10, 18 + 2(10) = 18 + 20 = 38
For x = 11, 18 + 2(11) = 18 + 22 = 40
For x = 12, 18 + 2(12) = 18 + 24 = 42
is that right?
GPT 3.5
I apologize for the mistake in my previous response. Let's verify if the numbers in the set are solutions to the inequality 18 + 2x ≥ 36 by evaluating each number:
For x = 9, 18 + 2(9) = 18 + 18 = 36 (9 is a solution)
For x = 10, 18 + 2(10) = 18 + 20 = 38 (10 is a solution)
For x = 11, 18 + 2(11) = 18 + 22 = 40 (11 is a solution)
For x = 12, 18 + 2(12) = 18 + 24 = 42 (12 is a solution)
Therefore, the correct set of numbers where all the numbers are solutions to the inequality 18 + 2x ≥ 36 is 9, 10, 11, 12. Thank you for pointing that out.
For x = 9, 18 + 2(9) = 18 + 18 = 36 (9 is a solution)
For x = 10, 18 + 2(10) = 18 + 20 = 38 (10 is a solution)
For x = 11, 18 + 2(11) = 18 + 22 = 40 (11 is a solution)
For x = 12, 18 + 2(12) = 18 + 24 = 42 (12 is a solution)
Therefore, the correct set of numbers where all the numbers are solutions to the inequality 18 + 2x ≥ 36 is 9, 10, 11, 12. Thank you for pointing that out.