To find the values of t for which the rocket's height is 29 meters, we set h equal to 29 and solve for t.
29 = 62t - 5t^2
5t^2 - 62t + 29 = 0
This is a quadratic equation that we can solve using the quadratic formula:
t = [-(-62) ± √((-62)^2 - 4*5*29)] / 2*5
t = [62 ± √(3844 - 580)] / 10
t = [62 ± √3264] / 10
t = [62 ± 57.14] / 10
So, the values of t for which the rocket's height is 29 meters are:
t ≈ 11.86 or t ≈ 1.14
A model rocket is launched with an initial upward velocity of 62 m/s The rocket's height h (in meters) after t seconds is given by the following.
h=62t-5t^2
Find all values of t for which the rocket's height is 29 meters.
Round your answer(s) to the nearest hundredth.
(If there is more than one answer, use the "or" button.)
1 answer
1 answer