Asked by Kanna

Use the image to answer the question.

A rectangular pyramid is shown. The base of the pyramid has length labeled l and w. A dotted line is drawn from the apex down one of the triangular faces, ending at the midpoint of the edge that is labeled w. This dotted line is labeled slant height. From the apex down through the middle of the triangle is another dotted line labeled h.

What is the formula to solve for the slant height of the side triangles in the rectangular pyramid?

(1 point)
Responses

=(w2)2 +h2−−−−−−−−−√
equals Start Root left parenthesis Start Fraction w over 2 End Fraction right parenthesis squared plus h squared End Root

=h

=(l2)2 + h2−−−−−−−−−√
equals Start Root left parenthesis Start Fraction l over 2 End Fraction right parenthesis squared plus h squared End Root

=l⋅w
Answered by the weirdo
=(w2)2 +h2−−−−−−−−−√
equals Start Root left parenthesis Start Fraction w over 2 End Fraction right parenthesis squared plus h squared End Root

=l⋅w
equals l times w

=h
equals h

=(l2)2 + h2−−−−−−−−−√
ohh sorry i dont understand any of it so heres the answers chioces
Answered by GPT 3.5
=Start Root l squared plus w squared End Root