Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
The molar mass of ammonium acetate is 77.083 g/mol. A student uses 0.100 mol of ammonium acetate in a chemical reaction. The st...Asked by iknj
The molar mass of ammonium acetate is 77.083 g/mol. A student uses 0.100 mol of ammonium acetate in a chemical reaction. The student claims that the reaction uses
(0.100 mol)(77.083 g/mol)=7.71 g of ammonium acetate, which has
(7.71)(6.022×1023)=4.64×1024 molecules.
(0.100 mol)(77.083 g/mol)=7.71 g of ammonium acetate, which has
(7.71)(6.022×1023)=4.64×1024 molecules.
Answers
Answered by
GPT 3.5
Is the student's claim correct?
To find the mass of 0.100 mol of ammonium acetate, we multiply the number of moles by the molar mass:
0.100 mol x 77.083 g/mol = 7.7083 g
So, the correct mass is 7.7083 g, not 7.71 g as stated by the student.
To find the number of molecules in 7.7083 g of ammonium acetate, we need to first convert the mass to moles:
7.7083 g / 77.083 g/mol = 0.1 mol
Now, we can use Avogadro's number to find the number of molecules:
0.1 mol x 6.022×10^23 molecules/mol = 6.022×10^22 molecules
Therefore, the correct number of molecules in 0.100 mol of ammonium acetate is 6.022×10^22, not 4.64×10^24 as claimed by the student.
To find the mass of 0.100 mol of ammonium acetate, we multiply the number of moles by the molar mass:
0.100 mol x 77.083 g/mol = 7.7083 g
So, the correct mass is 7.7083 g, not 7.71 g as stated by the student.
To find the number of molecules in 7.7083 g of ammonium acetate, we need to first convert the mass to moles:
7.7083 g / 77.083 g/mol = 0.1 mol
Now, we can use Avogadro's number to find the number of molecules:
0.1 mol x 6.022×10^23 molecules/mol = 6.022×10^22 molecules
Therefore, the correct number of molecules in 0.100 mol of ammonium acetate is 6.022×10^22, not 4.64×10^24 as claimed by the student.