Ming had 13 unsharpened pencils bundled in the shape of a cylinder. Of the diameter is 0.5 cm and the length is 19 cm, what is the surface area of Ming's bundle of pencils? Use 3.14 for π and round to the nearest tenth

Answer 1

First, let's calculate the surface area of the curved portion of the pencils:

Surface area of the curved portion = 2πr * h
r = radius = diameter / 2 = 0.5 cm / 2 = 0.25 cm
h = height = length = 19 cm

Surface area of the curved portion = 2 * 3.14 * 0.25 cm * 19 cm ≈ 29.9 cm²

Next, let's calculate the surface area of the two circular ends of the cylinder:

Surface area of one circular end = πr²
Surface area of two circular ends = 2 * π * (0.25 cm)² ≈ 0.4 cm²

Now, let's calculate the total surface area:

Total surface area = Surface area of the curved portion + Surface area of the two circular ends
Total surface area ≈ 29.9 cm² + 0.4 cm² ≈ 30.3 cm²

Therefore, the surface area of Ming's bundle of pencils is approximately 30.3 cm².