(1/2) m Vi^2 + m g h = (1/2) m Vfinal^2
or
Vfinal^2 = Vi^2 + 2 g h
= 225 + 2 (9.81)(20)
= 617.4
sqrt 617.4 = 24.8
27. Using energy considerations and assuming negligible air resistance,
show that a rock thrown from a bridge 20.0 m above water with an initial
speed of 15.0 m/s strikes the water with a speed of 24.8 m/s independent
of the direction thrown.
3 answers
24.8
I have a fought in the question value of m is not given .
Then how you have found the kinetic energy???
Then how you have found the kinetic energy???