To subtract the mixed number \( 27 \frac{5}{6} \) and the fraction \( \frac{2}{7} \), we can follow these steps: 1. **Convert the mixed number to an improper fraction**: \[ 27 \frac{5}{6} = 27 + \frac{5}{6} = \frac{27 \times 6 + 5}{6} = \frac{162 + 5}{6} = \frac{167}{6} \] 2. **Find a common denominator** for the fractions \( \frac{167}{6} \) and \( \frac{2}{7} \). The least common multiple (LCM) of 6 and 7 is 42. 3. **Convert both fractions to the common denominator**: - For \( \frac{167}{6} \): \[ \frac{167}{6} = \frac{167 \times 7}{6 \times 7} = \frac{1169}{42} \] - For \( \frac{2}{7} \): \[ \frac{2}{7} = \frac{2 \times 6}{7 \times 6} = \frac{12}{42} \] 4. **Now, subtract the fractions**: \[ \frac{1169}{42} - \frac{12}{42} = \frac{1169 - 12}{42} = \frac{1157}{42} \] 5. **Simplify the fraction if possible**: \( 1157 \) and \( 42 \) do not have common factors (since \( 1157 \) is not divisible by \( 2 \) or \( 3 \)), so this fraction is already in its simplest form. Thus, the result of the subtraction \( 27 \frac{5}{6} - \frac{2}{7} \) is: \[ \frac{1157}{42} \]

Yes, you are correct! The improper fraction \( \frac{1157}{42} \) can also be expressed as a mixed number or a decimal: 1. **Convert \( \frac{1157}{42} \) to a mixed number**: - Divide \( 1157 \) by \( 42 \): \[ 1157 \div 42 \approx 27.64 \] - The whole number part is \( 27 \). - To find the remainder: \[ 1157 - (27 \times 42) = 1157 - 1134 = 23 \] - So, \( \frac{1157}{42} \) can be written as: \[ 27 \frac{23}{42} \] Therefore, \( 27 \frac{5}{6} - \frac{2}{7} \) equals: \[ 27 \frac{23}{42} \] Again, I apologize for not clarifying the format earlier. Thank you for pointing it out!

27 5/6−2/7

To subtract the mixed number \( 27 \frac{5}{6} \) and the fraction \( \frac{2}{7} \), we can follow these steps:

Convert the mixed number to an improper fraction: \[ 27 \frac{5}{6} = 27 + \frac{5}{6} = \frac{27 \times 6 + 5}{6} = \frac{162 + 5}{6} = \frac{167}{6} \]
Find a common denominator for the fractions \( \frac{167}{6} \) and \( \frac{2}{7} \). The least common multiple (LCM) of 6 and 7 is 42.
Convert both fractions to the common denominator:
- For \( \frac{167}{6} \): \[ \frac{167}{6} = \frac{167 \times 7}{6 \times 7} = \frac{1169}{42} \]
- For \( \frac{2}{7} \): \[ \frac{2}{7} = \frac{2 \times 6}{7 \times 6} = \frac{12}{42} \]
Now, subtract the fractions: \[ \frac{1169}{42} - \frac{12}{42} = \frac{1169 - 12}{42} = \frac{1157}{42} \]
Simplify the fraction if possible: \( 1157 \) and \( 42 \) do not have common factors (since \( 1157 \) is not divisible by \( 2 \) or \( 3 \)), so this fraction is already in its simplest form.

Thus, the result of the subtraction \( 27 \frac{5}{6} - \frac{2}{7} \) is: \[ \frac{1157}{42} \]

did you mean: 1,157?

Yes, you are correct!

The improper fraction \( \frac{1157}{42} \) can also be expressed as a mixed number or a decimal:

Convert \( \frac{1157}{42} \) to a mixed number:
- Divide \( 1157 \) by \( 42 \): \[ 1157 \div 42 \approx 27.64 \]
- The whole number part is \( 27 \).
- To find the remainder: \[ 1157 - (27 \times 42) = 1157 - 1134 = 23 \]
- So, \( \frac{1157}{42} \) can be written as: \[ 27 \frac{23}{42} \]

Therefore, \( 27 \frac{5}{6} - \frac{2}{7} \) equals: \[ 27 \frac{23}{42} \]

Again, I apologize for not clarifying the format earlier. Thank you for pointing it out!