There is only one solution to the equation j^2 - 9 = -13.
j^2 - 9 = -13
j^2 = -13 + 9
j^2 = -4
j = ±√(-4)
Since the square root of -4 is not a real number, there is only one solution which is an imaginary number: j = ± 2i.
How many solutions does jpower2−9=−13 have?(1 point)
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How many solutions does jpower2−9=−13 have?(1 point)
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The equation j^2 - 9 = -13 has two solutions.
j^2 - 9 = -13
j^2 = -13 + 9
j^2 = -4
j = ±√(-4)
Since the square root of -4 is ±2i, the solutions to the equation are j = 2i and j = -2i. So, there are two solutions.
j^2 - 9 = -13
j^2 = -13 + 9
j^2 = -4
j = ±√(-4)
Since the square root of -4 is ±2i, the solutions to the equation are j = 2i and j = -2i. So, there are two solutions.